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(5x+4)(8x-3)=79
We move all terms to the left:
(5x+4)(8x-3)-(79)=0
We multiply parentheses ..
(+40x^2-15x+32x-12)-79=0
We get rid of parentheses
40x^2-15x+32x-12-79=0
We add all the numbers together, and all the variables
40x^2+17x-91=0
a = 40; b = 17; c = -91;
Δ = b2-4ac
Δ = 172-4·40·(-91)
Δ = 14849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{14849}}{2*40}=\frac{-17-\sqrt{14849}}{80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{14849}}{2*40}=\frac{-17+\sqrt{14849}}{80} $
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