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(5x+4)/(2x-7)=0
Domain of the equation: (2x-7)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
2x!=7
x!=7/2
x!=3+1/2
x∈R
(5x+4)=0
We get rid of parentheses
5x+4=0
We move all terms containing x to the left, all other terms to the right
5x=-4
x=-4/5
x=-4/5
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