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(5x+45)(x-30)=0
We multiply parentheses ..
(+5x^2-150x+45x-1350)=0
We get rid of parentheses
5x^2-150x+45x-1350=0
We add all the numbers together, and all the variables
5x^2-105x-1350=0
a = 5; b = -105; c = -1350;
Δ = b2-4ac
Δ = -1052-4·5·(-1350)
Δ = 38025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{38025}=195$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-195}{2*5}=\frac{-90}{10} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+195}{2*5}=\frac{300}{10} =30 $
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