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(5x+5)(3x+1)=0
We multiply parentheses ..
(+15x^2+5x+15x+5)=0
We get rid of parentheses
15x^2+5x+15x+5=0
We add all the numbers together, and all the variables
15x^2+20x+5=0
a = 15; b = 20; c = +5;
Δ = b2-4ac
Δ = 202-4·15·5
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-10}{2*15}=\frac{-30}{30} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+10}{2*15}=\frac{-10}{30} =-1/3 $
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