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(5x+5/5)-3=8/x
We move all terms to the left:
(5x+5/5)-3-(8/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(5x+1)-(+8/x)-3=0
We get rid of parentheses
5x-8/x+1-3=0
We multiply all the terms by the denominator
5x*x+1*x-3*x-8=0
We add all the numbers together, and all the variables
-2x+5x*x-8=0
Wy multiply elements
5x^2-2x-8=0
a = 5; b = -2; c = -8;
Δ = b2-4ac
Δ = -22-4·5·(-8)
Δ = 164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{164}=\sqrt{4*41}=\sqrt{4}*\sqrt{41}=2\sqrt{41}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{41}}{2*5}=\frac{2-2\sqrt{41}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{41}}{2*5}=\frac{2+2\sqrt{41}}{10} $
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