(5x+55)/3=(3+3x)/2

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Solution for (5x+55)/3=(3+3x)/2 equation: 



(5x+55)/3=(3+3x)/2

We move all terms to the left:

(5x+55)/3-((3+3x)/2)=0

We add all the numbers together, and all the variables

(5x+55)/3-((3x+3)/2)=0

We calculate fractions


5x/()+(-((3x+3)*3)/()=0



We calculate terms in parentheses: +(-((3x+3)*3)/(), so:

-((3x+3)*3)/(

We multiply all the terms by the denominator


-((3x+3)*3)



We calculate terms in parentheses: -((3x+3)*3), so:

(3x+3)*3

We multiply parentheses

9x+9

Back to the equation:

-(9x+9)



We get rid of parentheses

-9x-9

Back to the equation:

+(-9x-9)



We get rid of parentheses

5x/()-9x-9=0

We multiply all the terms by the denominator


5x-9x*()-9*()=0

We add all the numbers together, and all the variables

5x-9x*()=0

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