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(5x+6)(2x+3)=10x+2x-2
We move all terms to the left:
(5x+6)(2x+3)-(10x+2x-2)=0
We add all the numbers together, and all the variables
(5x+6)(2x+3)-(12x-2)=0
We get rid of parentheses
(5x+6)(2x+3)-12x+2=0
We multiply parentheses ..
(+10x^2+15x+12x+18)-12x+2=0
We get rid of parentheses
10x^2+15x+12x-12x+18+2=0
We add all the numbers together, and all the variables
10x^2+15x+20=0
a = 10; b = 15; c = +20;
Δ = b2-4ac
Δ = 152-4·10·20
Δ = -575
Delta is less than zero, so there is no solution for the equation
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