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(5x+6)(6x-7)=0
We multiply parentheses ..
(+30x^2-35x+36x-42)=0
We get rid of parentheses
30x^2-35x+36x-42=0
We add all the numbers together, and all the variables
30x^2+x-42=0
a = 30; b = 1; c = -42;
Δ = b2-4ac
Δ = 12-4·30·(-42)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5041}=71$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-71}{2*30}=\frac{-72}{60} =-1+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+71}{2*30}=\frac{70}{60} =1+1/6 $
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