(5x+6)(7x+4)+(3x+4)(x+8)=(19x+10)(2x+3)+39

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Solution for (5x+6)(7x+4)+(3x+4)(x+8)=(19x+10)(2x+3)+39 equation:



(5x+6)(7x+4)+(3x+4)(x+8)=(19x+10)(2x+3)+39
We move all terms to the left:
(5x+6)(7x+4)+(3x+4)(x+8)-((19x+10)(2x+3)+39)=0
We multiply parentheses ..
(+35x^2+20x+42x+24)+(3x+4)(x+8)-((19x+10)(2x+3)+39)=0
We calculate terms in parentheses: -((19x+10)(2x+3)+39), so:
(19x+10)(2x+3)+39
We multiply parentheses ..
(+38x^2+57x+20x+30)+39
We get rid of parentheses
38x^2+57x+20x+30+39
We add all the numbers together, and all the variables
38x^2+77x+69
Back to the equation:
-(38x^2+77x+69)
We get rid of parentheses
35x^2-38x^2+20x+42x+(3x+4)(x+8)-77x+24-69=0
We multiply parentheses ..
35x^2-38x^2+(+3x^2+24x+4x+32)+20x+42x-77x+24-69=0
We add all the numbers together, and all the variables
-3x^2+(+3x^2+24x+4x+32)-15x-45=0
We get rid of parentheses
-3x^2+3x^2+24x+4x-15x+32-45=0
We add all the numbers together, and all the variables
13x-13=0
We move all terms containing x to the left, all other terms to the right
13x=13
x=13/13
x=1

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