(5x+6)(x+1)=-(11x+2)

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Solution for (5x+6)(x+1)=-(11x+2) equation:


Simplifying
(5x + 6)(x + 1) = -1(11x + 2)

Reorder the terms:
(6 + 5x)(x + 1) = -1(11x + 2)

Reorder the terms:
(6 + 5x)(1 + x) = -1(11x + 2)

Multiply (6 + 5x) * (1 + x)
(6(1 + x) + 5x * (1 + x)) = -1(11x + 2)
((1 * 6 + x * 6) + 5x * (1 + x)) = -1(11x + 2)
((6 + 6x) + 5x * (1 + x)) = -1(11x + 2)
(6 + 6x + (1 * 5x + x * 5x)) = -1(11x + 2)
(6 + 6x + (5x + 5x2)) = -1(11x + 2)

Combine like terms: 6x + 5x = 11x
(6 + 11x + 5x2) = -1(11x + 2)

Reorder the terms:
6 + 11x + 5x2 = -1(2 + 11x)
6 + 11x + 5x2 = (2 * -1 + 11x * -1)
6 + 11x + 5x2 = (-2 + -11x)

Solving
6 + 11x + 5x2 = -2 + -11x

Solving for variable 'x'.

Reorder the terms:
6 + 2 + 11x + 11x + 5x2 = -2 + -11x + 2 + 11x

Combine like terms: 6 + 2 = 8
8 + 11x + 11x + 5x2 = -2 + -11x + 2 + 11x

Combine like terms: 11x + 11x = 22x
8 + 22x + 5x2 = -2 + -11x + 2 + 11x

Reorder the terms:
8 + 22x + 5x2 = -2 + 2 + -11x + 11x

Combine like terms: -2 + 2 = 0
8 + 22x + 5x2 = 0 + -11x + 11x
8 + 22x + 5x2 = -11x + 11x

Combine like terms: -11x + 11x = 0
8 + 22x + 5x2 = 0

Factor a trinomial.
(4 + x)(2 + 5x) = 0

Subproblem 1

Set the factor '(4 + x)' equal to zero and attempt to solve: Simplifying 4 + x = 0 Solving 4 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + x = 0 + -4 x = 0 + -4 Combine like terms: 0 + -4 = -4 x = -4 Simplifying x = -4

Subproblem 2

Set the factor '(2 + 5x)' equal to zero and attempt to solve: Simplifying 2 + 5x = 0 Solving 2 + 5x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 5x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 5x = 0 + -2 5x = 0 + -2 Combine like terms: 0 + -2 = -2 5x = -2 Divide each side by '5'. x = -0.4 Simplifying x = -0.4

Solution

x = {-4, -0.4}

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