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(5x+6)(x+6)=0
We multiply parentheses ..
(+5x^2+30x+6x+36)=0
We get rid of parentheses
5x^2+30x+6x+36=0
We add all the numbers together, and all the variables
5x^2+36x+36=0
a = 5; b = 36; c = +36;
Δ = b2-4ac
Δ = 362-4·5·36
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-24}{2*5}=\frac{-60}{10} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+24}{2*5}=\frac{-12}{10} =-1+1/5 $
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