(5x+60)+(2x+51)=(43-2x)+(30-10x)

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Solution for (5x+60)+(2x+51)=(43-2x)+(30-10x) equation: 



(5x+60)+(2x+51)=(43-2x)+(30-10x)

We move all terms to the left:

(5x+60)+(2x+51)-((43-2x)+(30-10x))=0

We add all the numbers together, and all the variables

(5x+60)+(2x+51)-((-2x+43)+(-10x+30))=0

We get rid of parentheses

5x+2x-((-2x+43)+(-10x+30))+60+51=0



We calculate terms in parentheses: -((-2x+43)+(-10x+30)), so:

(-2x+43)+(-10x+30)

We get rid of parentheses

-2x-10x+43+30

We add all the numbers together, and all the variables

-12x+73

Back to the equation:

-(-12x+73)



We add all the numbers together, and all the variables

7x-(-12x+73)+111=0

We get rid of parentheses

7x+12x-73+111=0

We add all the numbers together, and all the variables

19x+38=0

We move all terms containing x to the left, all other terms to the right

19x=-38

x=-38/19

x=-2

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