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(5x+62)(3x+47)=37
We move all terms to the left:
(5x+62)(3x+47)-(37)=0
We multiply parentheses ..
(+15x^2+235x+186x+2914)-37=0
We get rid of parentheses
15x^2+235x+186x+2914-37=0
We add all the numbers together, and all the variables
15x^2+421x+2877=0
a = 15; b = 421; c = +2877;
Δ = b2-4ac
Δ = 4212-4·15·2877
Δ = 4621
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(421)-\sqrt{4621}}{2*15}=\frac{-421-\sqrt{4621}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(421)+\sqrt{4621}}{2*15}=\frac{-421+\sqrt{4621}}{30} $
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