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(5x+6=-49-6x)x=
We move all terms to the left:
(5x+6-(-49-6x)x)=0
We add all the numbers together, and all the variables
(5x+6-(-6x-49)x)=0
We calculate terms in parentheses: +(5x+6-(-6x-49)x), so:We get rid of parentheses
5x+6-(-6x-49)x
determiningTheFunctionDomain 5x-(-6x-49)x+6
We multiply parentheses
6x^2+5x+49x+6
We add all the numbers together, and all the variables
6x^2+54x+6
Back to the equation:
+(6x^2+54x+6)
6x^2+54x+6=0
a = 6; b = 54; c = +6;
Δ = b2-4ac
Δ = 542-4·6·6
Δ = 2772
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2772}=\sqrt{36*77}=\sqrt{36}*\sqrt{77}=6\sqrt{77}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-6\sqrt{77}}{2*6}=\frac{-54-6\sqrt{77}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+6\sqrt{77}}{2*6}=\frac{-54+6\sqrt{77}}{12} $
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