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(5x+7)(3x-2)=0
We multiply parentheses ..
(+15x^2-10x+21x-14)=0
We get rid of parentheses
15x^2-10x+21x-14=0
We add all the numbers together, and all the variables
15x^2+11x-14=0
a = 15; b = 11; c = -14;
Δ = b2-4ac
Δ = 112-4·15·(-14)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-31}{2*15}=\frac{-42}{30} =-1+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+31}{2*15}=\frac{20}{30} =2/3 $
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