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(5x+7)(6x-1)=0
We multiply parentheses ..
(+30x^2-5x+42x-7)=0
We get rid of parentheses
30x^2-5x+42x-7=0
We add all the numbers together, and all the variables
30x^2+37x-7=0
a = 30; b = 37; c = -7;
Δ = b2-4ac
Δ = 372-4·30·(-7)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-47}{2*30}=\frac{-84}{60} =-1+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+47}{2*30}=\frac{10}{60} =1/6 $
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