(5x+7)/2=(3x+5)/4+2x+3

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Solution for (5x+7)/2=(3x+5)/4+2x+3 equation: 



(5x+7)/2=(3x+5)/4+2x+3

We move all terms to the left:

(5x+7)/2-((3x+5)/4+2x+3)=0



Domain of the equation: 4+2x+3)!=0

We move all terms containing x to the left, all other terms to the right

2x+3)!=-4

x∈R



We calculate fractions


(22x+28)/2x+(-((3x+5)*2)/2x=0

We multiply all the terms by the denominator


(22x+28)+(-((3x+5)*2)=0



We calculate terms in parentheses: +(-((3x+5)*2), so:

-((3x+5)*2



We get rid of parentheses

22x+(-((3x+5)*2)+28=0

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