(5x+7)/5=(3-10x)/7

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Solution for (5x+7)/5=(3-10x)/7 equation: 



(5x+7)/5=(3-10x)/7

We move all terms to the left:

(5x+7)/5-((3-10x)/7)=0

We add all the numbers together, and all the variables

(5x+7)/5-((-10x+3)/7)=0

We calculate fractions


5x/()+(-((-10x+3)*5)/()=0



We calculate terms in parentheses: +(-((-10x+3)*5)/(), so:

-((-10x+3)*5)/(

We multiply all the terms by the denominator


-((-10x+3)*5)



We calculate terms in parentheses: -((-10x+3)*5), so:

(-10x+3)*5

We multiply parentheses

-50x+15

Back to the equation:

-(-50x+15)



We get rid of parentheses

50x-15

Back to the equation:

+(50x-15)



We get rid of parentheses

5x/()+50x-15=0

We multiply all the terms by the denominator


5x+50x*()-15*()=0

We add all the numbers together, and all the variables

5x+50x*()=0

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