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(5x-1)(2x-4)=0
We multiply parentheses ..
(+10x^2-20x-2x+4)=0
We get rid of parentheses
10x^2-20x-2x+4=0
We add all the numbers together, and all the variables
10x^2-22x+4=0
a = 10; b = -22; c = +4;
Δ = b2-4ac
Δ = -222-4·10·4
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-18}{2*10}=\frac{4}{20} =1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+18}{2*10}=\frac{40}{20} =2 $
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