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(5x-1)(3x-2)=22
We move all terms to the left:
(5x-1)(3x-2)-(22)=0
We multiply parentheses ..
(+15x^2-10x-3x+2)-22=0
We get rid of parentheses
15x^2-10x-3x+2-22=0
We add all the numbers together, and all the variables
15x^2-13x-20=0
a = 15; b = -13; c = -20;
Δ = b2-4ac
Δ = -132-4·15·(-20)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-37}{2*15}=\frac{-24}{30} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+37}{2*15}=\frac{50}{30} =1+2/3 $
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