(5x-1)(4x+8)=0

Solution for (5x-1)(4x+8)=0 equation:

(5x-1)(4x+8)=0

We multiply parentheses ..

(+20x^2+40x-4x-8)=0

We get rid of parentheses

20x^2+40x-4x-8=0

We add all the numbers together, and all the variables

20x^2+36x-8=0

a = 20; b = 36; c = -8;
Δ = b2-4ac
Δ = 362-4·20·(-8)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-44}{2*20}=\frac{-80}{40}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+44}{2*20}=\frac{8}{40}
=1/5
$