(5x-1)(x+3)(x-5)(5x+1)=40

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Solution for (5x-1)(x+3)(x-5)(5x+1)=40 equation: 



(5x-1)(x+3)(x-5)(5x+1)=40

We move all terms to the left:

(5x-1)(x+3)(x-5)(5x+1)-(40)=0

We multiply parentheses ..

(+5x^2+15x-1x-3)(x-5)(5x+1)-40=0

We multiply parentheses ..

(+5x^2+15x-1x-3)(+5x^2+x-25x-5)-40=0

We move all terms containing x to the left, all other terms to the right

(+5x^2+15x-1x-3)(+5x^2+x-25x-5)=40

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