(5x-1)2=(3x+2)2+(4x-3)2

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Solution for (5x-1)2=(3x+2)2+(4x-3)2 equation: 



(5x-1)2=(3x+2)2+(4x-3)2

We move all terms to the left:

(5x-1)2-((3x+2)2+(4x-3)2)=0

We multiply parentheses

10x-((3x+2)2+(4x-3)2)-2=0



We calculate terms in parentheses: -((3x+2)2+(4x-3)2), so:

(3x+2)2+(4x-3)2

We multiply parentheses

6x+8x+4-6

We add all the numbers together, and all the variables

14x-2

Back to the equation:

-(14x-2)



We get rid of parentheses

10x-14x+2-2=0

We add all the numbers together, and all the variables

-4x=0

x=0/-4

x=0

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