(5x-10)(14+7x)=0

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Solution for (5x-10)(14+7x)=0 equation:



(5x-10)(14+7x)=0
We add all the numbers together, and all the variables
(5x-10)(7x+14)=0
We multiply parentheses ..
(+35x^2+70x-70x-140)=0
We get rid of parentheses
35x^2+70x-70x-140=0
We add all the numbers together, and all the variables
35x^2-140=0
a = 35; b = 0; c = -140;
Δ = b2-4ac
Δ = 02-4·35·(-140)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140}{2*35}=\frac{-140}{70} =-2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140}{2*35}=\frac{140}{70} =2 $

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