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(5x-10)(2x+14)=0
We multiply parentheses ..
(+10x^2+70x-20x-140)=0
We get rid of parentheses
10x^2+70x-20x-140=0
We add all the numbers together, and all the variables
10x^2+50x-140=0
a = 10; b = 50; c = -140;
Δ = b2-4ac
Δ = 502-4·10·(-140)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-90}{2*10}=\frac{-140}{20} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+90}{2*10}=\frac{40}{20} =2 $
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