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(5x-10)(3x+9)=0
We multiply parentheses ..
(+15x^2+45x-30x-90)=0
We get rid of parentheses
15x^2+45x-30x-90=0
We add all the numbers together, and all the variables
15x^2+15x-90=0
a = 15; b = 15; c = -90;
Δ = b2-4ac
Δ = 152-4·15·(-90)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-75}{2*15}=\frac{-90}{30} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+75}{2*15}=\frac{60}{30} =2 $
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