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(5x-10)(x+11)=0
We multiply parentheses ..
(+5x^2+55x-10x-110)=0
We get rid of parentheses
5x^2+55x-10x-110=0
We add all the numbers together, and all the variables
5x^2+45x-110=0
a = 5; b = 45; c = -110;
Δ = b2-4ac
Δ = 452-4·5·(-110)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-65}{2*5}=\frac{-110}{10} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+65}{2*5}=\frac{20}{10} =2 $
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