(5x-10)+(60-2x)+(x+60)=180

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Solution for (5x-10)+(60-2x)+(x+60)=180 equation:



(5x-10)+(60-2x)+(x+60)=180
We move all terms to the left:
(5x-10)+(60-2x)+(x+60)-(180)=0
We add all the numbers together, and all the variables
(5x-10)+(-2x+60)+(x+60)-180=0
We get rid of parentheses
5x-2x+x-10+60+60-180=0
We add all the numbers together, and all the variables
4x-70=0
We move all terms containing x to the left, all other terms to the right
4x=70
x=70/4
x=17+1/2

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