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(5x-11)(5x-3)=0
We multiply parentheses ..
(+25x^2-15x-55x+33)=0
We get rid of parentheses
25x^2-15x-55x+33=0
We add all the numbers together, and all the variables
25x^2-70x+33=0
a = 25; b = -70; c = +33;
Δ = b2-4ac
Δ = -702-4·25·33
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-40}{2*25}=\frac{30}{50} =3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+40}{2*25}=\frac{110}{50} =2+1/5 $
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