(5x-11)=(2x+20)=(11x-63)

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Solution for (5x-11)=(2x+20)=(11x-63) equation: 



(5x-11)=(2x+20)=(11x-63)

We move all terms to the left:

(5x-11)-((2x+20))=0

We get rid of parentheses

5x-((2x+20))-11=0



We calculate terms in parentheses: -((2x+20)), so:

(2x+20)

We get rid of parentheses

2x+20

Back to the equation:

-(2x+20)



We get rid of parentheses

5x-2x-20-11=0

We add all the numbers together, and all the variables

3x-31=0

We move all terms containing x to the left, all other terms to the right

3x=31

x=31/3

x=10+1/3

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