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(5*x-12)/12-(x/3) = x/12+3 // - x/12+3
(5*x-12)/12-(x/3)-(x/12)-3 = 0
(5*x-12)/12-x/3-x/12-3 = 0
(3*(5*x-12))/(3*12)+(12*(-x))/(3*12)+(3*(-x))/(3*12)+(-3*3*12)/(3*12) = 0
3*(5*x-12)+12*(-x)+3*(-x)-3*3*12 = 0
3*x-3*x-108-36 = 0
-108-36 = 0
-144 = 0
-144/(3*12) = 0
-144/(3*12) = 0 // * 3*12
-144 = 0
x belongs to the empty set
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