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(5x-15)(5x+40)=0
We multiply parentheses ..
(+25x^2+200x-75x-600)=0
We get rid of parentheses
25x^2+200x-75x-600=0
We add all the numbers together, and all the variables
25x^2+125x-600=0
a = 25; b = 125; c = -600;
Δ = b2-4ac
Δ = 1252-4·25·(-600)
Δ = 75625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{75625}=275$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(125)-275}{2*25}=\frac{-400}{50} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(125)+275}{2*25}=\frac{150}{50} =3 $
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