(5x-16)/(x-2)(x-5)=A+B

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Solution for (5x-16)/(x-2)(x-5)=A+B equation: 



(5x-16)/(x-2)(x-5)=+

We move all terms to the left:

(5x-16)/(x-2)(x-5)-(+)=0



Domain of the equation: (x-2)(x-5)!=0

We move all terms containing x to the left, all other terms to the right

x-2)(x!=5

x∈R



We add all the numbers together, and all the variables

(5x-16)/(x-2)(x-5)-0=0

We add all the numbers together, and all the variables

(5x-16)/(x-2)(x-5)=0

We multiply parentheses ..

(5x-16)/(+x^2-5x-2x+10)=0

We multiply all the terms by the denominator


(5x-16)=0

We get rid of parentheses

5x-16=0

We move all terms containing x to the left, all other terms to the right

5x=16

x=16/5

x=3+1/5

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