(5x-17)=(2x-4)+(x+4)

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Solution for (5x-17)=(2x-4)+(x+4) equation: 



(5x-17)=(2x-4)+(x+4)

We move all terms to the left:

(5x-17)-((2x-4)+(x+4))=0

We get rid of parentheses

5x-((2x-4)+(x+4))-17=0



We calculate terms in parentheses: -((2x-4)+(x+4)), so:

(2x-4)+(x+4)

We get rid of parentheses

2x+x-4+4

We add all the numbers together, and all the variables

3x

Back to the equation:

-(3x)



We add all the numbers together, and all the variables

2x-17=0

We move all terms containing x to the left, all other terms to the right

2x=17

x=17/2

x=8+1/2

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