(5x-17)=(x+4)+(2x-4)

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Solution for (5x-17)=(x+4)+(2x-4) equation: 



(5x-17)=(x+4)+(2x-4)

We move all terms to the left:

(5x-17)-((x+4)+(2x-4))=0

We get rid of parentheses

5x-((x+4)+(2x-4))-17=0



We calculate terms in parentheses: -((x+4)+(2x-4)), so:

(x+4)+(2x-4)

We get rid of parentheses

x+2x+4-4

We add all the numbers together, and all the variables

3x

Back to the equation:

-(3x)



We add all the numbers together, and all the variables

2x-17=0

We move all terms containing x to the left, all other terms to the right

2x=17

x=17/2

x=8+1/2

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