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(5x-18)(4x+45)=
We move all terms to the left:
(5x-18)(4x+45)-()=0
We add all the numbers together, and all the variables
(5x-18)(4x+45)=0
We multiply parentheses ..
(+20x^2+225x-72x-810)=0
We get rid of parentheses
20x^2+225x-72x-810=0
We add all the numbers together, and all the variables
20x^2+153x-810=0
a = 20; b = 153; c = -810;
Δ = b2-4ac
Δ = 1532-4·20·(-810)
Δ = 88209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{88209}=297$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(153)-297}{2*20}=\frac{-450}{40} =-11+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(153)+297}{2*20}=\frac{144}{40} =3+3/5 $
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