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(5x-2)(2x+7)=x
We move all terms to the left:
(5x-2)(2x+7)-(x)=0
We add all the numbers together, and all the variables
-1x+(5x-2)(2x+7)=0
We multiply parentheses ..
(+10x^2+35x-4x-14)-1x=0
We get rid of parentheses
10x^2+35x-4x-1x-14=0
We add all the numbers together, and all the variables
10x^2+30x-14=0
a = 10; b = 30; c = -14;
Δ = b2-4ac
Δ = 302-4·10·(-14)
Δ = 1460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1460}=\sqrt{4*365}=\sqrt{4}*\sqrt{365}=2\sqrt{365}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{365}}{2*10}=\frac{-30-2\sqrt{365}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{365}}{2*10}=\frac{-30+2\sqrt{365}}{20} $
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