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(5x-2)(5x-7)=0
We multiply parentheses ..
(+25x^2-35x-10x+14)=0
We get rid of parentheses
25x^2-35x-10x+14=0
We add all the numbers together, and all the variables
25x^2-45x+14=0
a = 25; b = -45; c = +14;
Δ = b2-4ac
Δ = -452-4·25·14
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-25}{2*25}=\frac{20}{50} =2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+25}{2*25}=\frac{70}{50} =1+2/5 $
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