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(5x-2)(6x+3)=0
We multiply parentheses ..
(+30x^2+15x-12x-6)=0
We get rid of parentheses
30x^2+15x-12x-6=0
We add all the numbers together, and all the variables
30x^2+3x-6=0
a = 30; b = 3; c = -6;
Δ = b2-4ac
Δ = 32-4·30·(-6)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-27}{2*30}=\frac{-30}{60} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+27}{2*30}=\frac{24}{60} =2/5 $
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