(5x-2)/2-(19x+6)/2x=(3x-2)/4

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Solution for (5x-2)/2-(19x+6)/2x=(3x-2)/4 equation: 


x in (-oo:+oo)

(5*x-2)/2-(x*((19*x+6)/2)) = (3*x-2)/4 // - (3*x-2)/4

(5*x-2)/2-(x*((19*x+6)/2))-((3*x-2)/4) = 0

(5*x-2)/2+(-1*x*(19*x+6))/2+(-1*(3*x-2))/4 = 0

(4*(5*x-2))/(2*4)+(-1*4*x*(19*x+6))/(2*4)+(-1*2*(3*x-2))/(2*4) = 0

4*(5*x-2)-1*4*x*(19*x+6)-1*2*(3*x-2) = 0

4-76*x^2-4*x-6*x-8 = 0

-76*x^2-10*x-4 = 0

-76*x^2-10*x-4 = 0

-2*(38*x^2+5*x+2) = 0

38*x^2+5*x+2 = 0

DELTA = 5^2-(2*4*38)

DELTA = -279

DELTA < 0

-2 = 0

-2/(2*4) = 0

-2/(2*4) = 0 // * 2*4

-2 = 0

x belongs to the empty set

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