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(5x-20)(x+11)=0
We multiply parentheses ..
(+5x^2+55x-20x-220)=0
We get rid of parentheses
5x^2+55x-20x-220=0
We add all the numbers together, and all the variables
5x^2+35x-220=0
a = 5; b = 35; c = -220;
Δ = b2-4ac
Δ = 352-4·5·(-220)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-75}{2*5}=\frac{-110}{10} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+75}{2*5}=\frac{40}{10} =4 $
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