(5x-20)+(30-2x)+(2x)+(3x+10)=360

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Solution for (5x-20)+(30-2x)+(2x)+(3x+10)=360 equation: 



(5x-20)+(30-2x)+(2x)+(3x+10)=360

We move all terms to the left:

(5x-20)+(30-2x)+(2x)+(3x+10)-(360)=0

We add all the numbers together, and all the variables

(5x-20)+(-2x+30)+2x+(3x+10)-360=0

We add all the numbers together, and all the variables

2x+(5x-20)+(-2x+30)+(3x+10)-360=0

We get rid of parentheses

2x+5x-2x+3x-20+30+10-360=0

We add all the numbers together, and all the variables

8x-340=0

We move all terms containing x to the left, all other terms to the right

8x=340

x=340/8

x=42+1/2

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