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(5x-20)=(2x+16)
We move all terms to the left:
(5x-20)-((2x+16))=0
We get rid of parentheses
5x-((2x+16))-20=0
We calculate terms in parentheses: -((2x+16)), so:We get rid of parentheses
(2x+16)
We get rid of parentheses
2x+16
Back to the equation:
-(2x+16)
5x-2x-16-20=0
We add all the numbers together, and all the variables
3x-36=0
We move all terms containing x to the left, all other terms to the right
3x=36
x=36/3
x=12
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