(5x-20)=4(x-2)

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Solution for (5x-20)=4(x-2) equation: 



(5x-20)=4(x-2)

We move all terms to the left:

(5x-20)-(4(x-2))=0

We get rid of parentheses

5x-(4(x-2))-20=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

5x-4x+8-20=0

We add all the numbers together, and all the variables

x-12=0

We move all terms containing x to the left, all other terms to the right

x=12

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