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(5x-21)(4x+1)=180
We move all terms to the left:
(5x-21)(4x+1)-(180)=0
We multiply parentheses ..
(+20x^2+5x-84x-21)-180=0
We get rid of parentheses
20x^2+5x-84x-21-180=0
We add all the numbers together, and all the variables
20x^2-79x-201=0
a = 20; b = -79; c = -201;
Δ = b2-4ac
Δ = -792-4·20·(-201)
Δ = 22321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-\sqrt{22321}}{2*20}=\frac{79-\sqrt{22321}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+\sqrt{22321}}{2*20}=\frac{79+\sqrt{22321}}{40} $
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