(5x-25)(3x-9)=0

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Solution for (5x-25)(3x-9)=0 equation:



(5x-25)(3x-9)=0
We multiply parentheses ..
(+15x^2-45x-75x+225)=0
We get rid of parentheses
15x^2-45x-75x+225=0
We add all the numbers together, and all the variables
15x^2-120x+225=0
a = 15; b = -120; c = +225;
Δ = b2-4ac
Δ = -1202-4·15·225
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-30}{2*15}=\frac{90}{30} =3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+30}{2*15}=\frac{150}{30} =5 $

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