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(5x-27)(4x)=90
We move all terms to the left:
(5x-27)(4x)-(90)=0
We multiply parentheses
20x^2-108x-90=0
a = 20; b = -108; c = -90;
Δ = b2-4ac
Δ = -1082-4·20·(-90)
Δ = 18864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18864}=\sqrt{144*131}=\sqrt{144}*\sqrt{131}=12\sqrt{131}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-12\sqrt{131}}{2*20}=\frac{108-12\sqrt{131}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+12\sqrt{131}}{2*20}=\frac{108+12\sqrt{131}}{40} $
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