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(5x-3)(2x-1)=0
We multiply parentheses ..
(+10x^2-5x-6x+3)=0
We get rid of parentheses
10x^2-5x-6x+3=0
We add all the numbers together, and all the variables
10x^2-11x+3=0
a = 10; b = -11; c = +3;
Δ = b2-4ac
Δ = -112-4·10·3
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-1}{2*10}=\frac{10}{20} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+1}{2*10}=\frac{12}{20} =3/5 $
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