If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(5x-3)(2x-5)=0
We multiply parentheses ..
(+10x^2-25x-6x+15)=0
We get rid of parentheses
10x^2-25x-6x+15=0
We add all the numbers together, and all the variables
10x^2-31x+15=0
a = 10; b = -31; c = +15;
Δ = b2-4ac
Δ = -312-4·10·15
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-19}{2*10}=\frac{12}{20} =3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+19}{2*10}=\frac{50}{20} =2+1/2 $
| a+3a-4=4 | | 6x-54=169 | | 10x+18=3x-17 | | q(5)=15-125 | | p(-9/16)=1/2-4/3(-9/16) | | g(12)=-12^2+9(12)-1 | | 5+3x=x-15 | | -x-14=-2x-7 | | (5x-7)-(2x+3)/6×+11=8/3 | | 90=1=10n-10 | | 1=10n-10 | | 27-2x=5x+627+6=5x-2x | | g(0.4)=-0.4^2+9(0.4)-1 | | 3x-6/2x+4=0 | | -2c+7+6c=27 | | g(-7)=-7^2+9(-7)-1 | | -9r-1+7r=15 | | 7k-8+2(k+12)=32 | | 3x3-39x+36=0 | | 2x(2)-5x+10=0 | | x+73,44=89,2 | | f(3/10)=-5(3/10)-14 | | –5p=–4p−4 | | 64^{-n+3}=16^{3n-1} | | 3x+4x=−21 | | x=4x-13 | | 2x(2)-5+10=0 | | G(25)=6x^2+1 | | (1+r)^10=18.877r+1 | | -14z/3=-28/33 | | -14z=-28/33 | | 3x–8=23 |