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(5x-3)(5x+7)=0
We multiply parentheses ..
(+25x^2+35x-15x-21)=0
We get rid of parentheses
25x^2+35x-15x-21=0
We add all the numbers together, and all the variables
25x^2+20x-21=0
a = 25; b = 20; c = -21;
Δ = b2-4ac
Δ = 202-4·25·(-21)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-50}{2*25}=\frac{-70}{50} =-1+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+50}{2*25}=\frac{30}{50} =3/5 $
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